Contact person: Business Client

Phone:Show

Email:Show

Location: Sonipat, India

Budget: Recommended by industry experts

Time to start: As soon as possible

Project description:
"#function for removing common characters
# with their respective occurrences


def remove_match_char(list1, list2):

for i in range(len(list1)):
for j in range(len(list2)):

# if common character is found
# then remove that character
# and return list of concatenated
# list with True Flag
if list1[i] == list2[j]:
c = list1[i]

# remove character from the list
[login to view URL](c)
[login to view URL](c)

# concatenation of two list elements with *
# * is act as border mark here
list3 = list1 + ["*"] + list2

# return the concatenated list with True flag
return [list3, True]

# no common characters is found
# return the concatenated list with False flag
list3 = list1 + ["*"] + list2
return [list3, False]


# Driver code
if __name__ == "__main__":

# take first name
p1 = input("Player 1 name : ")

# converted all letters into lower case
p1 = [login to view URL]()

# replace any space with empty string
[login to view URL](" ", "")

# make a list of letters or characters
p1_list = list(p1)

# take 2nd name
p2 = input("Player 2 name : ")
p2 = [login to view URL]()
[login to view URL](" ", "")
p2_list = list(p2)

# taking a flag as True initially
proceed = True

# keep calling remove_match_char function
# until common characters is found or
# keep looping until proceed flag is True
while proceed:

# function calling and store return value
ret_list = remove_match_char(p1_list, p2_list)

# take out concatenated list from return list
con_list = ret_list[0]

# take out flag value from return list
proceed = ret_list[1]

# find the index of "*" / border mark
star_index = [login to view URL]("*")

# list slicing perform

# all characters before * store in p1_list
p1_list = con_list[: star_index]

# all characters after * store in p2_list
p2_list = con_list[star_index + 1:]

# count total remaining characters
count = len(p1_list) + len(p2_list)

# list of FLAMES acronym
result = ["Friends", "Love", "Affection", "Marriage", "Enemy", "Siblings"]

# keep looping until only one item
# is not remaining in the result list
while len(result) > 1:

# store that index value from
# where we have to perform slicing.
split_index = (count % len(result) - 1)

# this steps is done for performing
# anticlock-wise circular fashion counting.
if split_index >= 0:

# list slicing
right = result[split_index + 1:]
left = result[: split_index]

# list concatenation
result = right + left

else:
result = result[: len(result) - 1]

# print final result
print("Relationship status :", result[0])" (client-provided description)